第4章 4.15

(1)

2x+1x(x+1)(x+2)\frac{2x+1}{x(x+1)(x+2)}

∫2x+1x(x+1)(x+2)dx=∫12{1x+2x+1−3x+2}dx=12log⁡∣x(x+1)2(x+2)3∣+C\int \frac{2x+1}{x(x+1)(x+2)}dx = \int \frac{1}{2}\left\{\frac{1}{x}+\frac{2}{x+1}-\frac{3}{x+2}\right\}dx = \frac{1}{2}\log\left|\frac{x(x+1)^2}{(x+2)^3}\right|+C

(Cは積分定数)

(2)

x3−x+4(x−1)(x−2)\frac{x^3-x+4}{(x-1)(x-2)}

∫x3−x+4(x−1)(x−2)dx=∫x3−x+4x2−3x+2dx=∫x+3+6x−2x2−3x+2dx=∫x+3+6x−2(x−1)(x−2)dx\int \frac{x^3-x+4}{(x-1)(x-2)}dx = \int \frac{x^3-x+4}{x^2-3x+2}dx = \int x+3+\frac{6x-2}{x^2-3x+2}dx = \int x+3+\frac{6x-2}{(x-1)(x-2)}dx

=∫x+3+(−4x−1+10x−2)dx=12x2+3x+log⁡(x−2)10(x−1)4+C=\int x+3+\left(\frac{-4}{x-1}+\frac{10}{x-2}\right)dx = \frac{1}{2}x^2+3x+\log\frac{(x-2)^{10}}{(x-1)^4}+C

(Cは積分定数)

(3)

4x+19(x2+4)(x+1)2\frac{4x+19}{(x^2+4)(x+1)^2}

∫4x+19(x2+4)(x+1)2dx=∫{−2x−1(x2+4)+2x+5(x+1)2}dx=∫{−2xx2+4+−1x2+4+2x+2x2+2x+1+3(x+1)2}dx\int \frac{4x+19}{(x^2+4)(x+1)^2}dx = \int \left\{\frac{-2x-1}{(x^2+4)}+\frac{2x+5}{(x+1)^2}\right\}dx = \int \left\{\frac{-2x}{x^2+4}+\frac{-1}{x^2+4}+\frac{2x+2}{x^2+2x+1}+\frac{3}{(x+1)^2}\right\}dx

=−12tan⁡−1x2+log⁡(x+1)2x2+4−3x+1+C=-\frac{1}{2}\tan^{-1}\frac{x}{2}+\log\frac{(x+1)^2}{x^2+4}-\frac{3}{x+1}+C

(Cは積分定数)

(4)

x2x4−1\frac{x^2}{x^4-1}

∫x2x4−1dx=∫x2(x2−1)(x2+1)dx=∫x2(x−1)(x+1)(x2+1)dx\int \frac{x^2}{x^4-1}dx = \int \frac{x^2}{(x^2-1)(x^2+1)}dx = \int \frac{x^2}{(x-1)(x+1)(x^2+1)}dx

=∫14(1x−1+−1x+1+2x2+1)dx=12tan⁡−1x+14log⁡∣x−1x+1∣+C=\int \frac{1}{4}\left(\frac{1}{x-1}+\frac{-1}{x+1}+\frac{2}{x^2+1}\right)dx = \frac{1}{2}\tan^{-1}x+\frac{1}{4}\log\left|\frac{x-1}{x+1}\right|+C

(Cは積分定数)

解説: r31bn1z