第14章 14.8

(1)

S=12bc⋅sin⁡A=12⋅5⋅4⋅sin⁡60=10⋅32=53S = \frac{1}{2}bc \cdot \sin A = \frac{1}{2} \cdot 5 \cdot 4 \cdot \sin 60 = 10 \cdot \frac{\sqrt{3}}{2} = 5\sqrt{3}

(2)

s=12(a+b+c)=12(13+14+15)=21s = \frac{1}{2}(a+b+c) = \frac{1}{2}(13+14+15) = 21

S=s(s−a)(s−b)(s−c)=21⋅8⋅7⋅6=7056=84S = \sqrt{s(s-a)(s-b)(s-c)} = \sqrt{21 \cdot 8 \cdot 7 \cdot 6} = \sqrt{7056} = 84

(3)

A=180−60−45=75A = 180 - 60 - 45 = 75

sin⁡75=sin⁡(30+45)=sin⁡30cos⁡45+cos⁡30sin⁡45=1+322\sin 75 = \sin(30+45) = \sin 30 \cos 45 + \cos 30 \sin 45 = \frac{1+\sqrt{3}}{2\sqrt{2}}

b=sin⁡Bsin⁡Aa=sin⁡60sin⁡753=321+3223=361+3b = \frac{\sin B}{\sin A}a = \frac{\sin 60}{\sin 75}3 = \frac{\dfrac{\sqrt{3}}{2}}{\dfrac{1+\sqrt{3}}{2\sqrt{2}}}3 = \frac{3\sqrt{6}}{1+\sqrt{3}}

S=12ab⋅sin⁡C=12961+312=932(1+3)=943(−1+3)=94(3−3)S = \frac{1}{2}ab \cdot \sin C = \frac{1}{2}\frac{9\sqrt{6}}{1+\sqrt{3}}\frac{1}{\sqrt{2}} = \frac{9\sqrt{3}}{2(1+\sqrt{3})} = \frac{9}{4}\sqrt{3}(-1+\sqrt{3}) = \frac{9}{4}(3-\sqrt{3})

(4)

s=12(a+b+c)=27s = \frac{1}{2}(a+b+c) = 27

S=s(s−a)(s−b)(s−c)=27⋅14⋅7⋅6=15876=126S = \sqrt{s(s-a)(s-b)(s-c)} = \sqrt{27 \cdot 14 \cdot 7 \cdot 6} = \sqrt{15876} = 126

解説: r31bn1z