第14章 14.3

(1)

C=180−39−64=77°C = 180 - 39 - 64 = 77°

a=bsin⁡Asin⁡B=32sin⁡39°sin⁡64°=22a = b\frac{\sin A}{\sin B} = 32\frac{\sin 39°}{\sin 64°} = 22

c=bsin⁡Csin⁡B=32sin⁡77°sin⁡64°=35c = b\frac{\sin C}{\sin B} = 32\frac{\sin 77°}{\sin 64°} = 35

(2)

a2=b2+c2−2bccos⁡A=472+522−2⋅47⋅52⋅cos⁡69°=3161a=56a^2 = b^2 + c^2 - 2bc\cos A = 47^2 + 52^2 - 2 \cdot 47 \cdot 52 \cdot \cos 69° = 3161 \qquad a = 56

sin⁡B=basin⁡A=4756sin⁡69°=0.78B=51°\sin B = \frac{b}{a}\sin A = \frac{47}{56}\sin 69° = 0.78 \qquad B = 51°

C=180−69−51=60°C = 180 - 69 - 51 = 60°

(3)

cos⁡A=−a2+b2+c22bc=−342+892+11822⋅89⋅118=0.985A=10°\cos A = \frac{-a^2 + b^2 + c^2}{2bc} = \frac{-34^2 + 89^2 + 118^2}{2 \cdot 89 \cdot 118} = 0.985 \qquad A = 10°

cos⁡B=a2−b2+c22ac=342−892+11822⋅34⋅118=0.892B=27°\cos B = \frac{a^2 - b^2 + c^2}{2ac} = \frac{34^2 - 89^2 + 118^2}{2 \cdot 34 \cdot 118} = 0.892 \qquad B = 27°

C=180−10−27=143°C = 180 - 10 - 27 = 143°

解説: r31bn1z