第8章 8.17

(1)

y=x+2y = x + 2 xx と yy を入れ替えると

x=y+2x = y + 2 y=x−2y = x - 2

(2)

y=x+2y = \sqrt{x + 2} xx と yy を入れ替えると

x=y+2x = \sqrt{y + 2} x2=y+2x^2 = y + 2 y=x2−2y = x^2 - 2 ただし x≥0x \geq 0

(3)

y=1−x2y = 1 - x^2 (x≥0)(x \geq 0) xx と yy を入れ替えると

x=1−y2x = 1 - y^2 y=1−xy = \sqrt{1 - x} ただし x≤1x \leq 1

(4)

y=2−xx−1y = \dfrac{2 - x}{x - 1} xx と yy を入れ替えると

x=2−yy−1=−1+1y−1x = \dfrac{2 - y}{y - 1} = -1 + \dfrac{1}{y - 1} x+1=1y−1x + 1 = \dfrac{1}{y - 1} y−1=1x+1y - 1 = \dfrac{1}{x + 1} y=1x+1+1y = \dfrac{1}{x + 1} + 1

(5)

y=4x+3x+2y = \dfrac{4x + 3}{x + 2} xx と yy を入れ替えると

x=4y+3y+2=4−5y+2x = \dfrac{4y + 3}{y + 2} = 4 - \dfrac{5}{y + 2} 4−x=5y+24 - x = \dfrac{5}{y + 2} y+2=−5x−4y + 2 = -\dfrac{5}{x - 4} y=−5x−4−2y = -\dfrac{5}{x - 4} - 2

解説: r31bn1z