第8章 8.17

(1)

y=x+2y = x + 2 xxyy を入れ替えると

x=y+2x = y + 2 y=x2y = x - 2

(2)

y=x+2y = \sqrt{x + 2} xxyy を入れ替えると

x=y+2x = \sqrt{y + 2} x2=y+2x^2 = y + 2 y=x22y = x^2 - 2 ただし x0x \geq 0

(3)

y=1x2y = 1 - x^2 (x0)(x \geq 0) xxyy を入れ替えると

x=1y2x = 1 - y^2 y=1xy = \sqrt{1 - x} ただし x1x \leq 1

(4)

y=2xx1y = \dfrac{2 - x}{x - 1} xxyy を入れ替えると

x=2yy1=1+1y1x = \dfrac{2 - y}{y - 1} = -1 + \dfrac{1}{y - 1} x+1=1y1x + 1 = \dfrac{1}{y - 1} y1=1x+1y - 1 = \dfrac{1}{x + 1} y=1x+1+1y = \dfrac{1}{x + 1} + 1

(5)

y=4x+3x+2y = \dfrac{4x + 3}{x + 2} xxyy を入れ替えると

x=4y+3y+2=45y+2x = \dfrac{4y + 3}{y + 2} = 4 - \dfrac{5}{y + 2} 4x=5y+24 - x = \dfrac{5}{y + 2} y+2=5x4y + 2 = -\dfrac{5}{x - 4} y=5x42y = -\dfrac{5}{x - 4} - 2

解説: r31bn1z