2(x−3+32)(x−3−32)=2x2−2(3+3+3−32)x+2(3+32)(3−32)=2x2−6x+2⋅9−342\left(x - \frac{3+\sqrt{3}}{2}\right)\left(x - \frac{3-\sqrt{3}}{2}\right) = 2x^2 - 2\left(\frac{3+\sqrt{3}+3-\sqrt{3}}{2}\right)x + 2\left(\frac{3+\sqrt{3}}{2}\right)\left(\frac{3-\sqrt{3}}{2}\right) = 2x^2 - 6x + 2\cdot\frac{9-3}{4}2(x−23+3)(x−23−3)=2x2−2(23+3+3−3)x+2(23+3)(23−3)=2x2−6x+2⋅49−3 =2x2−6x+3= 2x^2 - 6x + 3=2x2−6x+3 これから a=−6a = -6a=−6 b=−3b = -3b=−3 となる