第3章 3.13

(1)

y=xexy = xe^x

y′=ex+xexy' = e^x + xe^x

y′′=ex+ex+xex=2ex+xexy'' = e^x + e^x + xe^x = 2e^x + xe^x

これから

y(n)=nex+xexy^{(n)} = ne^x + xe^x

(2)

y=x2exy = x^2 e^x

y′=2xex+x2exy' = 2xe^x + x^2 e^x

y′′=2ex+2xex+2xex+x2ex=2ex+4xex+x2exy'' = 2e^x + 2xe^x + 2xe^x + x^2 e^x = 2e^x + 4xe^x + x^2 e^x

y′′′=2ex+4ex+4xex+2xex+x2ex=6ex+6xex+x2exy''' = 2e^x + 4e^x + 4xe^x + 2xe^x + x^2 e^x = 6e^x + 6xe^x + x^2 e^x

y(4)=6ex+6ex+6xex+2xex+x2ex=12ex+8xex+x2exy^{(4)} = 6e^x + 6e^x + 6xe^x + 2xe^x + x^2 e^x = 12e^x + 8xe^x + x^2 e^x

y(n)=n(n−1)ex+2nxex+x2exy^{(n)} = n(n-1)e^x + 2nxe^x + x^2 e^x

(3)

y=exsin⁡xy = e^x \sin x

y′=exsin⁡x+excos⁡xy' = e^x \sin x + e^x \cos x

y′′=exsin⁡x+excos⁡x+excos⁡x−exsin⁡x=2excos⁡xy'' = e^x \sin x + e^x \cos x + e^x \cos x - e^x \sin x = 2e^x \cos x

y′′′=2excos⁡x−2exsin⁡xy''' = 2e^x \cos x - 2e^x \sin x

y(4)=2excos⁡x−2exsin⁡x−2exsin⁡x−2excos⁡x=−4exsin⁡xy^{(4)} = 2e^x \cos x - 2e^x \sin x - 2e^x \sin x - 2e^x \cos x = -4e^x \sin x

これから y(n)=(2)nexsin⁡(x+π4n)y^{(n)} = (\sqrt{2})^n e^x \sin\left(x + \frac{\pi}{4} n\right)

(4)

y=xsin⁡xy = x \sin x

y′=sin⁡x+xcos⁡xy' = \sin x + x \cos x

y′′=cos⁡x+cos⁡x−xsin⁡x=2cos⁡x−xsin⁡xy'' = \cos x + \cos x - x \sin x = 2\cos x - x \sin x

これから

y(n)=nsin⁡{x+π2(n−1)}+xsin⁡(x+π2n)y^{(n)} = n \sin\left\{x + \frac{\pi}{2}(n-1)\right\} + x \sin\left(x + \frac{\pi}{2}n\right)

解説: r31bn1z