(1) 2(2a+b)−3(a−b)=2{2(x+2y)+(3x−y)}−3{(x+2y)−(3x−y)}=16x−3y2(2a+b)-3(a-b)=2\{2(x+2y)+(3x-y)\}-3\{(x+2y)-(3x-y)\}=16x-3y2(2a+b)−3(a−b)=2{2(x+2y)+(3x−y)}−3{(x+2y)−(3x−y)}=16x−3y (2) {x+2y=a①3x−y=b②\begin{cases} x+2y=a & ① \\ 3x-y=b & ② \end{cases}{x+2y=a3x−y=b①② ①+②×2 7x=a+2b7x=a+2b7x=a+2b x=17a+27bx=\dfrac{1}{7}a+\dfrac{2}{7}bx=71a+72b ①×3-② 7y=3a−b7y=3a-b7y=3a−b y=37a−17by=\dfrac{3}{7}a-\dfrac{1}{7}by=73a−71b