(1) AD⃗=12b\vec{AD} = \frac{1}{2}bAD=21b (2) DE⃗=−12b+12c\vec{DE} = -\frac{1}{2}b + \frac{1}{2}cDE=−21b+21c (3) EB⃗=(−12c+12b)+12b=b−12c\vec{EB} = \left(-\frac{1}{2}c + \frac{1}{2}b\right) + \frac{1}{2}b = b - \frac{1}{2}cEB=(−21c+21b)+21b=b−21c (4) CD⃗=−c+12b\vec{CD} = -c + \frac{1}{2}bCD=−c+21b