第6章 6.3

(1)

$y = x^x$

両辺の対数をとると

$\log y = x \cdot \log x$

$\frac{y'}{y} = \log x + x \cdot \frac{1}{x} = \log x + 1 \qquad y' = y(\log x + 1) = x^x(\log x + 1)$

(2)

$y = 3^{2x}$

両辺の対数を取ると

$\log y = 2x \cdot \log 3$

$\frac{y'}{y} = 2 \cdot \log 3 \qquad y' = 2y \cdot \log 3 \qquad y' = 2 \cdot 3^{2x} \cdot \log 3$