第16章 16.2

(1)

x2+2x+y2=(x+1)21+y2=0(x+1)2+y2=1x^2 + 2x + y^2 = (x+1)^2 - 1 + y^2 = 0 \qquad (x+1)^2 + y^2 = 1

中心(1,0)(-1,0) 半径11

(2)

x2+2y+y2=x2+(y+1)21=0x2+(y+1)2=1x^2 + 2y + y^2 = x^2 + (y+1)^2 - 1 = 0 \qquad x^2 + (y+1)^2 = 1

中心(0,1)(0,-1) 半径11

(3)

x2+y23x+4y=(x32)294+(y+2)24=0(x32)2+(y+2)2=254x^2 + y^2 - 3x + 4y = \left(x-\frac{3}{2}\right)^2 - \frac{9}{4} + (y+2)^2 - 4 = 0 \qquad \left(x-\frac{3}{2}\right)^2 + (y+2)^2 = \frac{25}{4}

中心(32,2)\left(\dfrac{3}{2}, -2\right) 半径52\dfrac{5}{2}

(4)

2x2+2y2+4x6y7=2(x+1)22+2(y32)2927=0(x+1)2+(y32)2=2742x^2 + 2y^2 + 4x - 6y - 7 = 2(x+1)^2 - 2 + 2\left(y-\frac{3}{2}\right)^2 - \frac{9}{2} - 7 = 0 \qquad (x+1)^2 + \left(y-\frac{3}{2}\right)^2 = \frac{27}{4}

中心(1,32)\left(-1, \dfrac{3}{2}\right) 半径332\dfrac{3\sqrt{3}}{2}

解説: r31bn1z