第13章 13.23

cos⁡4θ=2cos⁡22θ−1=2{2cos⁡2θ−1}2−1=8cos⁡4θ−8cos⁡2θ+2−1\cos 4\theta = 2\cos^2 2\theta - 1 = 2\{2\cos^2\theta - 1\}^2 - 1 = 8\cos^4\theta - 8\cos^2\theta + 2 - 1

=8cos⁡4θ−8cos⁡2θ+1=8x4−8x2+1= 8\cos^4\theta - 8\cos^2\theta + 1 = 8x^4 - 8x^2 + 1

解説: r31bn1z