第13章 13.23

cos4θ=2cos22θ1=2{2cos2θ1}21=8cos4θ8cos2θ+21\cos 4\theta = 2\cos^2 2\theta - 1 = 2\{2\cos^2\theta - 1\}^2 - 1 = 8\cos^4\theta - 8\cos^2\theta + 2 - 1

=8cos4θ8cos2θ+1=8x48x2+1= 8\cos^4\theta - 8\cos^2\theta + 1 = 8x^4 - 8x^2 + 1

解説: r31bn1z