第13章 13.10

(1)

sinx1=0sinx=1x=π2,52π,x=π2+2nπ\sin x - 1 = 0 \qquad \sin x = 1 \qquad x = \frac{\pi}{2}, \frac{5}{2}\pi, \cdots \qquad x = \frac{\pi}{2} + 2n\pi

(2)

2sinx+1=0sinx=12x=76π+2nπ,π6+2nπ2\sin x + 1 = 0 \qquad \sin x = -\frac{1}{2} \qquad x = \frac{7}{6}\pi + 2n\pi, -\frac{\pi}{6} + 2n\pi

(3)

tanx+1=0tanx=1x=3π4+nπ\tan x + 1 = 0 \qquad \tan x = -1 \qquad x = \frac{3\pi}{4} + n\pi

(4)

cosx2cos2x=0cosx(12cosx)=0cosx=0,12x=π2+nπ,±π3+2nπ\cos x - 2\cos^2 x = 0 \qquad \cos x(1 - 2\cos x) = 0 \qquad \cos x = 0, \frac{1}{2} \qquad x = \frac{\pi}{2} + n\pi, \pm\frac{\pi}{3} + 2n\pi

(5)

2sin2x+sinx1=0(2sinx1)(sinx+1)=0sinx=12,12\sin^2 x + \sin x - 1 = 0 \qquad (2\sin x - 1)(\sin x + 1) = 0 \qquad \sin x = \frac{1}{2}, -1

x=π6+2nπ,56π+2nπ,32π+2nπx = \frac{\pi}{6} + 2n\pi, \frac{5}{6}\pi + 2n\pi, \frac{3}{2}\pi + 2n\pi

(6)

cos2x3cosx+2=0(cosx2)(cosx1)=0cosx=1x=2nπ\cos^2 x - 3\cos x + 2 = 0 \qquad (\cos x - 2)(\cos x - 1) = 0 \qquad \cos x = 1 \qquad x = 2n\pi

(7)

sin2x+sinx=02sinxcosx+sinx=0sinx(2cosx+1)=0sinx=0cosx=12\sin 2x + \sin x = 0 \qquad 2\sin x \cos x + \sin x = 0 \qquad \sin x(2\cos x + 1) = 0 \qquad \sin x = 0 \qquad \cos x = -\frac{1}{2}

(2n+1)π,23π+2nπ,43π+2nπ(2n+1)\pi, \frac{2}{3}\pi + 2n\pi, \frac{4}{3}\pi + 2n\pi

(8)

cos2x+sin2x=0cos2xsin2x+sin2x=0cos2x=0x=π2+nπ\cos 2x + \sin^2 x = 0 \qquad \cos^2 x - \sin^2 x + \sin^2 x = 0 \qquad \cos^2 x = 0 \qquad x = \frac{\pi}{2} + n\pi

解説: r31bn1z