第13章 13.9

sinx+cosx=65\sin x + \cos x = \frac{6}{5}

(sinx+cosx)2=3625sin2x+2sinxcosx+cos2x=36252sinxcosx=36251=1125(\sin x + \cos x)^2 = \frac{36}{25} \qquad \sin^2 x + 2\sin x \cos x + \cos^2 x = \frac{36}{25} \qquad 2\sin x \cos x = \frac{36}{25} - 1 = \frac{11}{25}

sin2x=2sinxcosx=1125\sin 2x = 2\sin x \cdot \cos x = \frac{11}{25}

解説: r31bn1z