第13章 13.9

sin⁡x+cos⁡x=65\sin x + \cos x = \frac{6}{5}

(sin⁡x+cos⁡x)2=3625sin⁡2x+2sin⁡xcos⁡x+cos⁡2x=36252sin⁡xcos⁡x=3625−1=1125(\sin x + \cos x)^2 = \frac{36}{25} \qquad \sin^2 x + 2\sin x \cos x + \cos^2 x = \frac{36}{25} \qquad 2\sin x \cos x = \frac{36}{25} - 1 = \frac{11}{25}

sin⁡2x=2sin⁡x⋅cos⁡x=1125\sin 2x = 2\sin x \cdot \cos x = \frac{11}{25}

解説: r31bn1z