塔の地点を Q、PQ=h とすると h=AQtan27°=BQtan40°h = AQ\tan27° = BQ\tan40°h=AQtan27°=BQtan40° であり AQ2+BQ2=AB2AQ^2 + BQ^2 = AB^2AQ2+BQ2=AB2 となる これから (htan27°)2+(htan40°)2=2002h2(tan227°+tan240°)=2002tan227°tan240°\left(\frac{h}{\tan27°}\right)^2 + \left(\frac{h}{\tan40°}\right)^2 = 200^2 \qquad h^2(\tan^2 27° + \tan^2 40°) = 200^2 \tan^2 27° \tan^2 40°(tan27°h)2+(tan40°h)2=2002h2(tan227°+tan240°)=2002tan227°tan240° h2(0.26+0.7)=7311.7h2=7616h=87.27h^2(0.26 + 0.7) = 7311.7 \qquad h^2 = 7616 \qquad h = 87.27h2(0.26+0.7)=7311.7h2=7616h=87.27 約87.27m