第10章 10.9

(1)

log⁡6=log⁡2+log⁡3=0.3010+0.4771=0.7781\log 6 = \log 2 + \log 3 = 0.3010 + 0.4771 = 0.7781

(2)

log⁡5=log⁡10−log⁡2=1−0.3010=0.6990\log 5 = \log 10 - \log 2 = 1 - 0.3010 = 0.6990

(3)

log⁡1.5=log⁡3−log⁡2=0.4771−0.3010=0.1761\log 1.5 = \log 3 - \log 2 = 0.4771 - 0.3010 = 0.1761

(4)

log⁡25=log⁡5+log⁡5=0.6990+0.6990=1.3980\log 25 = \log 5 + \log 5 = 0.6990 + 0.6990 = 1.3980

(5)

log⁡23=log⁡2−log⁡3=0.3010−0.4771=−0.1761\log \frac{2}{3} = \log 2 - \log 3 = 0.3010 - 0.4771 = -0.1761

(6)

log⁡13=−12log⁡3=−12⋅0.4771=−0.2386\log \frac{1}{\sqrt{3}} = -\frac{1}{2}\log 3 = -\frac{1}{2} \cdot 0.4771 = -0.2386

(7)

log⁡0.027=log⁡27−log⁡1000=3log⁡3−3=3⋅0.4771−3=−1.5687\log 0.027 = \log 27 - \log 1000 = 3\log 3 - 3 = 3 \cdot 0.4771 - 3 = -1.5687

(8)

log⁡23=log⁡103log⁡102=0.47710.3010=1.5850\log_2 3 = \frac{\log_{10} 3}{\log_{10} 2} = \frac{0.4771}{0.3010} = 1.5850

(9)

log⁡188=log⁡108log⁡1018=3log⁡2log⁡2+log⁡3+log⁡3=3⋅0.30100.3010+0.4771+0.4771=0.7194\log_{18} 8 = \frac{\log_{10} 8}{\log_{10} 18} = \frac{3\log 2}{\log 2 + \log 3 + \log 3} = \frac{3 \cdot 0.3010}{0.3010 + 0.4771 + 0.4771} = 0.7194

解説: r31bn1z