f(0):(0)2−2(0)=0
f(2):(2)2−2(2)=0
f(−3):(−3)2−2(−3)=15
f(−x):x2−2x
f(x+1):(x+1)2−2(x+1)=x2+2x+1−2x−2=x2−1
f(a+h):(a+h)2−2(a+h)=a2+2ah+h2−2a−2h
f(a):a2−2a
f(a+h)−f(a):2ah+h2−2h=h(2a+h−2)
f(0):(0)2−2(0)=0
f(2):(2)2−2(2)=0
f(−3):(−3)2−2(−3)=15
f(−x):x2−2x
f(x+1):(x+1)2−2(x+1)=x2+2x+1−2x−2=x2−1
f(a+h):(a+h)2−2(a+h)=a2+2ah+h2−2a−2h
f(a):a2−2a
f(a+h)−f(a):2ah+h2−2h=h(2a+h−2)
解説: r31bn1z