第3章 3.2

(1)

(0,−3)(0, -3)

y−(−3)=−3x2y=−3x2−3y - (-3) = -3x^2 \qquad y = -3x^2 - 3

(2)

(2,4)(2, 4)

y−4=−3(x−2)2y=−3(x−2)2+4y - 4 = -3(x-2)^2 \qquad y = -3(x-2)^2 + 4

(3)

(−2,4)(-2, 4)

y−4=−3(x−(−2))2y=−3(x+2)2+4y - 4 = -3\left(x - (-2)\right)^2 \qquad y = -3(x+2)^2 + 4

(4)

(−1,−2)(-1, -2)

y−(−2)=−3(x−(−1))2y=−3(x+1)2−2y - (-2) = -3\left(x - (-1)\right)^2 \qquad y = -3(x+1)^2 - 2

解説: r31bn1z