第3章 3.1

(1)

$(3,0)$

$y = (x-3)^2$

(2)

$(2,3)$

$y - 3 = (x-2)^2 \qquad y = (x-2)^2 + 3$

(3)

$(1,-2)$

$y - (-2) = (x-1)^2 \qquad y = (x-1)^2 - 2$

(4)

$(-2,1)$

$y - 1 = \left(x - (-2)\right)^2 \qquad y = (x+2)^2 + 1$