x4−3x3+2x2−1A=x2+1+3x−2A\frac{x^4 - 3x^3 + 2x^2 - 1}{A} = x^2 + 1 + \frac{3x - 2}{A}Ax4−3x3+2x2−1=x2+1+A3x−2 x4−3x3+2x2−1=A(x2+1)+3x−2x^4 - 3x^3 + 2x^2 - 1 = A(x^2 + 1) + 3x - 2x4−3x3+2x2−1=A(x2+1)+3x−2 A=x4−3x3+2x2−3x+1x2+1=x2−3x+1A = \frac{x^4 - 3x^3 + 2x^2 - 3x + 1}{x^2 + 1} = x^2 - 3x + 1A=x2+1x4−3x3+2x2−3x+1=x2−3x+1