第11章 11.6

(1)

2+3i2 + 3i

∣2+3i∣=4+9=13|2 + 3i| = \sqrt{4 + 9} = \sqrt{13}

(2)

1−4i1 - 4i

∣1−4i∣=1+16=17|1 - 4i| = \sqrt{1 + 16} = \sqrt{17}

(3)

−2+i-\sqrt{2} + i

∣−2+i∣=2+1=3|-\sqrt{2} + i| = \sqrt{2 + 1} = \sqrt{3}

(4)

−3i-3i

∣−3i∣=3|-3i| = 3

解説: r31bn1z