(1)
∫01∫12(x−y)dydx=∫01[xy−21y2]12dx=∫012x−2−x+21dx=∫01x−23dx=[21x2−23x]01=−1
(2)
∫−11∫01xy2dxdy=∫−11[21x2y2]01dy=∫−1121y2dy=[61y3]−11=31
(3)
∫0a∫0bxy(x−y)dydx=∫0a[21x2y2−31xy3]0bdx=∫0a21b2x2−31b3xdx=[61b2x3−61b3x2]0a
=61(a3b2−a2b3)