第3章 3.4

(1)

cos⁡2x\cos 2x

f=cos⁡2xf = \cos 2x とおくと

f′=−2sin⁡2xf′′=−4cos⁡2xf′′′=8sin⁡2xこれからf(n)=2ncos⁡(2x+π2n)f' = -2\sin 2x \qquad f'' = -4\cos 2x \qquad f''' = 8\sin 2x \qquad \text{これから} \qquad f^{(n)} = 2^{n}\cos\left(2x + \frac{\pi}{2}n\right)

(2)

sin⁡2x\sin^{2}x

f=sin⁡2xf = \sin^{2}x とおくと

f′=2sin⁡x⋅cos⁡x=sin⁡2xf' = 2\sin x \cdot \cos x = \sin 2x

f′′=2cos⁡2xf′′′=−4sin⁡2xこれからf(n)=2n−1sin⁡{2x+π2(n−1)}f'' = 2\cos 2x \qquad f''' = -4\sin 2x \qquad \text{これから} \qquad f^{(n)} = 2^{n-1}\sin\left\{2x + \frac{\pi}{2}(n-1)\right\}

(3)

axa^{x}

f=axf = a^{x} とおくと

f′=axlog⁡af′′=axlog⁡a⋅log⁡a=ax(log⁡a)2これからf(n)=ax(log⁡a)nf' = a^{x}\log a \qquad f'' = a^{x}\log a \cdot \log a = a^{x}(\log a)^{2} \qquad \text{これから} \qquad f^{(n)} = a^{x}(\log a)^{n}

(4)

xlog⁡xx\log x

f=xlog⁡xf = x\log x とおくと

f′=log⁡x+x⋅1x=log⁡x+1f′′=1xf′′′=−1x2f' = \log x + x \cdot \frac{1}{x} = \log x + 1 \qquad f'' = \frac{1}{x} \qquad f''' = -\frac{1}{x^{2}}

これから

f′=log⁡x+1f(n)=(−1)n(n−2)!xn−1f' = \log x + 1 \qquad f^{(n)} = (-1)^{n}\frac{(n-2)!}{x^{n-1}}

解説: r31bn1z