第1章 1.13

(1)

rsin⁡θ=1r\sin\theta = 1

y=rsin⁡θy = r\sin\theta から y=1y = 1

(2)

rcos⁡θ=−2r\cos\theta = -2

x=rcos⁡θx = r\cos\theta から x=−2x = -2

(3)

θ=π3\theta = \frac{\pi}{3}

θ=tan⁡−1yx\theta = \tan^{-1}\dfrac{y}{x} tan⁡θ=yx\tan\theta = \dfrac{y}{x} から tan⁡π3=yx\tan\dfrac{\pi}{3} = \dfrac{y}{x} 3=yx\sqrt{3} = \dfrac{y}{x} ∴y=3x\therefore y = \sqrt{3}x

(4)

r=3r = 3

r=x2+y2r = \sqrt{x^2 + y^2} から x2+y2=3\sqrt{x^2 + y^2} = 3 ∴x2+y2=9\therefore x^2 + y^2 = 9

(5)

r=2cos⁡θr = 2\cos\theta

r2=2rcos⁡θr^2 = 2r\cos\theta r=x2+y2r = \sqrt{x^2 + y^2} x=rcos⁡θx = r\cos\theta から ∴x2+y2=2x\therefore x^2 + y^2 = 2x

(6)

r=4sin⁡θr = 4\sin\theta

r2=4rsin⁡θr^2 = 4r\sin\theta r=x2+y2r = \sqrt{x^2 + y^2} y=rsin⁡θy = r\sin\theta から ∴x2+y2=4y\therefore x^2 + y^2 = 4y

解説: r31bn1z