第16章 16.19

(1)

{x+2y+3z+4u=22x−y+z−u=−43x+y+4z+3u=−2x+3y+4z+5u=2\begin{cases} x + 2y + 3z + 4u = 2 \\ 2x - y + z - u = -4 \\ 3x + y + 4z + 3u = -2 \\ x + 3y + 4z + 5u = 2 \end{cases}

[1234∣22−11−1∣−43143∣−21345∣2]→[1234∣20−5−5−9∣−80−5−5−9∣−80111∣0]→[1234∣20−5−5−9∣−80000∣00111∣0]\begin{bmatrix} 1 & 2 & 3 & 4 & | & 2 \\ 2 & -1 & 1 & -1 & | & -4 \\ 3 & 1 & 4 & 3 & | & -2 \\ 1 & 3 & 4 & 5 & | & 2 \end{bmatrix} \to \begin{bmatrix} 1 & 2 & 3 & 4 & | & 2 \\ 0 & -5 & -5 & -9 & | & -8 \\ 0 & -5 & -5 & -9 & | & -8 \\ 0 & 1 & 1 & 1 & | & 0 \end{bmatrix} \to \begin{bmatrix} 1 & 2 & 3 & 4 & | & 2 \\ 0 & -5 & -5 & -9 & | & -8 \\ 0 & 0 & 0 & 0 & | & 0 \\ 0 & 1 & 1 & 1 & | & 0 \end{bmatrix}

→[1234∣20111∣00559∣80000∣0]→[1012∣20111∣00004∣80000∣0]→[1010∣−20110∣−20001∣20000∣0]\to \begin{bmatrix} 1 & 2 & 3 & 4 & | & 2 \\ 0 & 1 & 1 & 1 & | & 0 \\ 0 & 5 & 5 & 9 & | & 8 \\ 0 & 0 & 0 & 0 & | & 0 \end{bmatrix} \to \begin{bmatrix} 1 & 0 & 1 & 2 & | & 2 \\ 0 & 1 & 1 & 1 & | & 0 \\ 0 & 0 & 0 & 4 & | & 8 \\ 0 & 0 & 0 & 0 & | & 0 \end{bmatrix} \to \begin{bmatrix} 1 & 0 & 1 & 0 & | & -2 \\ 0 & 1 & 1 & 0 & | & -2 \\ 0 & 0 & 0 & 1 & | & 2 \\ 0 & 0 & 0 & 0 & | & 0 \end{bmatrix}

よって (xyzu)=k(−1−110)+(−2−202)(k は任意定数)\begin{pmatrix} x \\ y \\ z \\ u \end{pmatrix} = k\begin{pmatrix} -1 \\ -1 \\ 1 \\ 0 \end{pmatrix} + \begin{pmatrix} -2 \\ -2 \\ 0 \\ 2 \end{pmatrix} \quad \text{(k は任意定数)}

(2)

{4x+2y+3z+w=1x+y−2w=25x+2y+4z−w=0\begin{cases} 4x + 2y + 3z + w = 1 \\ x + y - 2w = 2 \\ 5x + 2y + 4z - w = 0 \end{cases}

[4231∣1110−2∣2524−1∣0]→[110−2∣24231∣1524−1∣0]→[110−2∣20−239∣−70−349∣−10]\begin{bmatrix} 4 & 2 & 3 & 1 & | & 1 \\ 1 & 1 & 0 & -2 & | & 2 \\ 5 & 2 & 4 & -1 & | & 0 \end{bmatrix} \to \begin{bmatrix} 1 & 1 & 0 & -2 & | & 2 \\ 4 & 2 & 3 & 1 & | & 1 \\ 5 & 2 & 4 & -1 & | & 0 \end{bmatrix} \to \begin{bmatrix} 1 & 1 & 0 & -2 & | & 2 \\ 0 & -2 & 3 & 9 & | & -7 \\ 0 & -3 & 4 & 9 & | & -10 \end{bmatrix}

→[101−2∣−101−10∣30019∣−1]→[100−11∣00109∣20019∣−1]\to \begin{bmatrix} 1 & 0 & 1 & -2 & | & -1 \\ 0 & 1 & -1 & 0 & | & 3 \\ 0 & 0 & 1 & 9 & | & -1 \end{bmatrix} \to \begin{bmatrix} 1 & 0 & 0 & -11 & | & 0 \\ 0 & 1 & 0 & 9 & | & 2 \\ 0 & 0 & 1 & 9 & | & -1 \end{bmatrix}

よって (xyzw)=k(11−9−91)+(02−10)(k は任意定数)\begin{pmatrix} x \\ y \\ z \\ w \end{pmatrix} = k\begin{pmatrix} 11 \\ -9 \\ -9 \\ 1 \end{pmatrix} + \begin{pmatrix} 0 \\ 2 \\ -1 \\ 0 \end{pmatrix} \quad \text{(k は任意定数)}

(3)

{ax+y+z=1x+ay+z=ax+y+az=a2\begin{cases} ax + y + z = 1 \\ x + ay + z = a \\ x + y + az = a^2 \end{cases}

a=1a = 1のとき x+y+z=1x + y + z = 1

[a1111a1a11aa2]→[11aa21a1aa111]→[11aa20a−11−aa−a201−a1−a21−a3]→[11aa201−1−a011+a1+a+a2]\left[\begin{array}{ccc|c} a & 1 & 1 & 1 \\ 1 & a & 1 & a \\ 1 & 1 & a & a^2 \end{array}\right] \to \left[\begin{array}{ccc|c} 1 & 1 & a & a^2 \\ 1 & a & 1 & a \\ a & 1 & 1 & 1 \end{array}\right] \to \left[\begin{array}{ccc|c} 1 & 1 & a & a^2 \\ 0 & a-1 & 1-a & a-a^2 \\ 0 & 1-a & 1-a^2 & 1-a^3 \end{array}\right] \to \left[\begin{array}{ccc|c} 1 & 1 & a & a^2 \\ 0 & 1 & -1 & -a \\ 0 & 1 & 1+a & 1+a+a^2 \end{array}\right]

→[10a+1a2+a01−1−a00a+21+2a+a2]→[10a+1a(a+1)01−1−a001(1+a)2/(a+2)]\to \left[\begin{array}{ccc|c} 1 & 0 & a+1 & a^2+a \\ 0 & 1 & -1 & -a \\ 0 & 0 & a+2 & 1+2a+a^2 \end{array}\right] \to \left[\begin{array}{ccc|c} 1 & 0 & a+1 & a(a+1) \\ 0 & 1 & -1 & -a \\ 0 & 0 & 1 & (1+a)^2/(a+2) \end{array}\right]

→[100a(a+1)−(1+a)3a+2010−a+(1+a)2a+2001(1+a)2a+2]→[100−a+1a+20101a+2001(1+a)2a+2]\to \left[\begin{array}{ccc|c} 1 & 0 & 0 & a(a+1)-\frac{(1+a)^3}{a+2} \\ 0 & 1 & 0 & -a+\frac{(1+a)^2}{a+2} \\ 0 & 0 & 1 & \frac{(1+a)^2}{a+2} \end{array}\right] \to \left[\begin{array}{ccc|c} 1 & 0 & 0 & -\frac{a+1}{a+2} \\ 0 & 1 & 0 & \frac{1}{a+2} \\ 0 & 0 & 1 & \frac{(1+a)^2}{a+2} \end{array}\right]

a=2a = 2のとき解なし

a≠1,a≠2a \neq 1, a \neq 2のとき

(xyz)=(−a+1a+21a+2(1+a)2a+2)\begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} -\frac{a+1}{a+2} \\ \frac{1}{a+2} \\ \frac{(1+a)^2}{a+2} \end{pmatrix}

解説: r31bn1z