(1) x≠0x \neq 0x=0のとき f(x)′=2x⋅sin1x+x2⋅(−1x2)⋅cos1x=2x⋅sin1x−cos1xf'_{(x)} = 2x \cdot \sin\frac{1}{x} + x^2 \cdot \left(-\frac{1}{x^2}\right) \cdot \cos\frac{1}{x} = 2x \cdot \sin\frac{1}{x} - \cos\frac{1}{x}f(x)′=2x⋅sinx1+x2⋅(−x21)⋅cosx1=2x⋅sinx1−cosx1 x=0x = 0x=0のとき f(x)′=0f'_{(x)} = 0f(x)′=0 (2) f(0)′=2⋅0sin10−cos10f'_{(0)} = 2 \cdot 0\sin\frac{1}{0} - \cos\frac{1}{0}f(0)′=2⋅0sin01−cos01 となり、f(0)′f'_{(0)}f(0)′の値は存在しない。→ f(0)′f'_{(0)}f(0)′はx = 0において不連続である