第6章 6.13

(1)

cosh⁡2x−sinh⁡2x=(ex+e−x2)2−(ex−e−x2)2=e2x+2+e−2x−e2x+2−e−2x4=1\cosh^2 x - \sinh^2 x = \left(\frac{e^x+e^{-x}}{2}\right)^2 - \left(\frac{e^x-e^{-x}}{2}\right)^2 = \frac{e^{2x}+2+e^{-2x}-e^{2x}+2-e^{-2x}}{4} = 1

(2)

(sinh⁡x)′=(ex−e−x2)′=12(ex+e−x)=cosh⁡x(\sinh x)' = \left(\frac{e^x-e^{-x}}{2}\right)' = \frac{1}{2}(e^x+e^{-x}) = \cosh x

(3)

(cosh⁡x)′=(ex+e−x2)′=12(ex−e−x)=sinh⁡x(\cosh x)' = \left(\frac{e^x+e^{-x}}{2}\right)' = \frac{1}{2}(e^x-e^{-x}) = \sinh x

(4)

(tanh⁡x)′=(sinh⁡xcosh⁡x)′=(ex−e−xex+e−x)′=(ex+e−x)(ex+e−x)−(ex−e−x)(ex−e−x)(ex+e−x)2(\tanh x)' = \left(\frac{\sinh x}{\cosh x}\right)' = \left(\frac{e^x-e^{-x}}{e^x+e^{-x}}\right)' = \frac{(e^x+e^{-x})(e^x+e^{-x})-(e^x-e^{-x})(e^x-e^{-x})}{(e^x+e^{-x})^2}

=e2x+2+e−2x−e2x+2−e−2x(ex+e−x)2=1(ex+e−x2)2=1cosh⁡2x= \frac{e^{2x}+2+e^{-2x}-e^{2x}+2-e^{-2x}}{(e^x+e^{-x})^2} = \frac{1}{\left(\dfrac{e^x+e^{-x}}{2}\right)^2} = \frac{1}{\cosh^2 x}

解説: r31bn1z