第6章 6.1

(1)

y′=(2x−3)′2x−3=22x−3y'=\frac{(2x-3)'}{2x-3}=\frac{2}{2x-3}

(2)

y′=(x2+2x+2)′x2+2x+2=2x+2x2+2x+2y'=\frac{(x^2+2x+2)'}{x^2+2x+2}=\frac{2x+2}{x^2+2x+2}

(3)

y′=(1−x2)′1−x2=−2x21−x21−x2=−x1−x2=xx2−1y'=\frac{(\sqrt{1-x^2})'}{\sqrt{1-x^2}}=\frac{\dfrac{-2x}{2\sqrt{1-x^2}}}{\sqrt{1-x^2}}=\frac{-x}{1-x^2}=\frac{x}{x^2-1}

(4)

y′=2x⋅log⁡x+x2⋅1x=2xlog⁡x+xy'=2x\cdot\log x+x^2\cdot\frac{1}{x}=2x\log x+x

(5)

y′=0−(1+1x)(x+log⁡x)2=−x+1x(x+log⁡x)2=x+1x(x+log⁡x)2y'=\frac{0-\left(1+\dfrac{1}{x}\right)}{(x+\log x)^2}=-\frac{\dfrac{x+1}{x}}{(x+\log x)^2}=\frac{x+1}{x(x+\log x)^2}

(6)

y′=log⁡(x2+1)+x⋅2xx2+1=log⁡(x2+1)+2x2x2+1y'=\log(x^2+1)+x\cdot\frac{2x}{x^2+1}=\log(x^2+1)+\frac{2x^2}{x^2+1}

解説: r31bn1z