第12章 12.2

(1)

sin2θ+cos2θ=1sin2θ=1cos2θsinθ=1cos2θ\sin^2\theta + \cos^2\theta = 1 \qquad \sin^2\theta = 1 - \cos^2\theta \qquad \sin\theta = \sqrt{1-\cos^2\theta}

(2)

tanθ=sinθcosθ=1cos2θcosθ\tan\theta = \frac{\sin\theta}{\cos\theta} = \frac{\sqrt{1-\cos^2\theta}}{\cos\theta}

解説: r31bn1z