第12章 12.2

(1)

sin⁡2θ+cos⁡2θ=1sin⁡2θ=1−cos⁡2θsin⁡θ=1−cos⁡2θ\sin^2\theta + \cos^2\theta = 1 \qquad \sin^2\theta = 1 - \cos^2\theta \qquad \sin\theta = \sqrt{1-\cos^2\theta}

(2)

tan⁡θ=sin⁡θcos⁡θ=1−cos⁡2θcos⁡θ\tan\theta = \frac{\sin\theta}{\cos\theta} = \frac{\sqrt{1-\cos^2\theta}}{\cos\theta}

解説: r31bn1z