第10章 10.15

(1)

alog⁡cb=blog⁡caa^{\log_c b} = b^{\log_c a}

両辺、底が cc の対数をとると

log⁡calog⁡cb=log⁡cblog⁡calog⁡calog⁡cb=log⁡calog⁡cb\log_c a^{\log_c b} = \log_c b^{\log_c a} \qquad \log_c a \log_c b = \log_c a \log_c b

よって等式は成り立つ

(2)

log⁡aclog⁡abc=1+log⁡ab\dfrac{\log_a c}{\log_{ab} c} = 1 + \log_a b

左辺 =log⁡aclog⁡aclog⁡aab=log⁡aab=log⁡aa+log⁡ab=1+log⁡ab== \dfrac{\log_a c}{\dfrac{\log_a c}{\log_a ab}} = \log_a ab = \log_a a + \log_a b = 1 + \log_a b = 右辺

よって等式は成り立つ

解説: r31bn1z