第10章 10.15

(1)

alogcb=blogcaa^{\log_c b} = b^{\log_c a}

両辺、底が cc の対数をとると

logcalogcb=logcblogcalogcalogcb=logcalogcb\log_c a^{\log_c b} = \log_c b^{\log_c a} \qquad \log_c a \log_c b = \log_c a \log_c b

よって等式は成り立つ

(2)

logaclogabc=1+logab\dfrac{\log_a c}{\log_{ab} c} = 1 + \log_a b

左辺 =logaclogaclogaab=logaab=logaa+logab=1+logab== \dfrac{\log_a c}{\dfrac{\log_a c}{\log_a ab}} = \log_a ab = \log_a a + \log_a b = 1 + \log_a b = 右辺

よって等式は成り立つ

解説: r31bn1z