(1) alogcb=blogcaa^{\log_c b} = b^{\log_c a}alogcb=blogca 両辺、底が ccc の対数をとると logcalogcb=logcblogcalogcalogcb=logcalogcb\log_c a^{\log_c b} = \log_c b^{\log_c a} \qquad \log_c a \log_c b = \log_c a \log_c blogcalogcb=logcblogcalogcalogcb=logcalogcb よって等式は成り立つ (2) logaclogabc=1+logab\dfrac{\log_a c}{\log_{ab} c} = 1 + \log_a blogabclogac=1+logab 左辺 =logaclogaclogaab=logaab=logaa+logab=1+logab== \dfrac{\log_a c}{\dfrac{\log_a c}{\log_a ab}} = \log_a ab = \log_a a + \log_a b = 1 + \log_a b ==logaablogaclogac=logaab=logaa+logab=1+logab= 右辺 よって等式は成り立つ