第10章 10.1

(1)

33=27log⁡333=log⁡3273=log⁡3273^3 = 27 \qquad \log_3 3^3 = \log_3 27 \qquad 3 = \log_3 27

(2)

52=25log⁡552=log⁡5252=log⁡5255^2 = 25 \qquad \log_5 5^2 = \log_5 25 \qquad 2 = \log_5 25

(3)

30=1log⁡330=log⁡310=log⁡313^0 = 1 \qquad \log_3 3^0 = \log_3 1 \qquad 0 = \log_3 1

(4)

4−2=116log⁡44−2=log⁡4116−2=log⁡41164^{-2} = \dfrac{1}{16} \qquad \log_4 4^{-2} = \log_4 \dfrac{1}{16} \qquad -2 = \log_4 \dfrac{1}{16}

(5)

2−6=164log⁡22−6=log⁡2164−6=log⁡21642^{-6} = \dfrac{1}{64} \qquad \log_2 2^{-6} = \log_2 \dfrac{1}{64} \qquad -6 = \log_2 \dfrac{1}{64}

(6)

813=2log⁡8813=log⁡8213=log⁡828^{\frac{1}{3}} = 2 \qquad \log_8 8^{\frac{1}{3}} = \log_8 2 \qquad \dfrac{1}{3} = \log_8 2

(7)

(14)2=116log⁡14(14)2=log⁡141162=log⁡14116\left(\dfrac{1}{4}\right)^2 = \dfrac{1}{16} \qquad \log_{\frac{1}{4}} \left(\dfrac{1}{4}\right)^2 = \log_{\frac{1}{4}} \dfrac{1}{16} \qquad 2 = \log_{\frac{1}{4}} \dfrac{1}{16}

(8)

(12)−2=4log⁡12(12)−2=log⁡124−2=log⁡124\left(\dfrac{1}{2}\right)^{-2} = 4 \qquad \log_{\frac{1}{2}} \left(\dfrac{1}{2}\right)^{-2} = \log_{\frac{1}{2}} 4 \qquad -2 = \log_{\frac{1}{2}} 4

(9)

8134=27log⁡818134=log⁡812734=log⁡812781^{\frac{3}{4}} = 27 \qquad \log_{81} 81^{\frac{3}{4}} = \log_{81} 27 \qquad \dfrac{3}{4} = \log_{81} 27

(10)

71=7log⁡771=log⁡771=log⁡777^1 = 7 \qquad \log_7 7^1 = \log_7 7 \qquad 1 = \log_7 7

解説: r31bn1z