(1) ∣x−3∣=2|x-3|=2∣x−3∣=2 (x−3)2=4x2−6x+9=4x2−6x+5=0(x−5)(x−1)=0x=1,5(x-3)^2=4 \qquad x^2-6x+9=4 \qquad x^2-6x+5=0 \qquad (x-5)(x-1)=0 \qquad x=1,5(x−3)2=4x2−6x+9=4x2−6x+5=0(x−5)(x−1)=0x=1,5 (2) ∣1−x∣=5|1-x|=5∣1−x∣=5 (1−x)2=251−2x+x2=25x2−2x−24=0(x−6)(x+4)=0x=6,−4(1-x)^2=25 \qquad 1-2x+x^2=25 \qquad x^2-2x-24=0 \qquad (x-6)(x+4)=0 \qquad x=6,-4(1−x)2=251−2x+x2=25x2−2x−24=0(x−6)(x+4)=0x=6,−4 (3) ∣2x−3∣=7|2x-3|=7∣2x−3∣=7 (2x−3)2=494x2−12x+9=494x2−12x−40=04(x2−3x−10)=4(x−5)(x+2)=0(2x-3)^2=49 \qquad 4x^2-12x+9=49 \qquad 4x^2-12x-40=0 \qquad 4(x^2-3x-10)=4(x-5)(x+2)=0(2x−3)2=494x2−12x+9=494x2−12x−40=04(x2−3x−10)=4(x−5)(x+2)=0 x=5,−2x=5,-2x=5,−2