第2章 2.2

(1)

∣0+2∣+∣0−3∣=2+3=5|0 + 2| + |0 - 3| = 2 + 3 = 5

(2)

∣3+2∣+∣3−3∣=5|3 + 2| + |3 - 3| = 5

(3)

∣−1+2∣+∣−1−3∣=1+4=5|-1 + 2| + |-1 - 3| = 1 + 4 = 5

(4)

∣−3+2∣+∣−3−3∣=1+6=7|-3 + 2| + |-3 - 3| = 1 + 6 = 7

解説: r31bn1z