第1章 1.41

(1)

7ab212x2y×8bx21a2y÷b29ay3=2b39xy2a×9ay3b2=2byx\frac{7ab^2}{12x^2y} \times \frac{8bx}{21a^2y} \div \frac{b^2}{9ay^3} = \frac{2b^3}{9xy^2a} \times \frac{9ay^3}{b^2} = \frac{2by}{x}

(2)

(−xy)2z×3z2x3y÷6yz(−zy2)3=3yzx×z3y66yz=−y6z32x\frac{(-xy)^2}{z} \times \frac{3z^2}{x^3y} \div \frac{6yz}{(-zy^2)^3} = \frac{3yz}{x} \times \frac{z^3y^6}{6yz} = -\frac{y^6z^3}{2x}

(3)

2x−1x2−2x+1×x2−3x+24x2−1=2x−1(x−1)2×(x−2)(x−1)(2x−1)(2x+1)=x−2(x−1)(2x+1)\frac{2x-1}{x^2-2x+1} \times \frac{x^2-3x+2}{4x^2-1} = \frac{2x-1}{(x-1)^2} \times \frac{(x-2)(x-1)}{(2x-1)(2x+1)} = \frac{x-2}{(x-1)(2x+1)}

(4)

u2+2u−3u2−4×u2+5u−14u2+8u+15=(u+3)(u−1)(u−2)(u+2)×(u+7)(u−2)(u+3)(u+5)=(u−1)(u+7)(u+2)(u+5)=u2+6u−7u2+7u+10\frac{u^2+2u-3}{u^2-4} \times \frac{u^2+5u-14}{u^2+8u+15} = \frac{(u+3)(u-1)}{(u-2)(u+2)} \times \frac{(u+7)(u-2)}{(u+3)(u+5)} = \frac{(u-1)(u+7)}{(u+2)(u+5)} = \frac{u^2+6u-7}{u^2+7u+10}

(5)

2x2+x−3x2−2x−3÷2x2+5x+3x2−4x+3×x3+1x3−1=(2x+3)(x−1)(x−3)(x+1)×(x−3)(x−1)(2x+3)(x+1)×(x+1)(x2−x+1)(x−1)(x2+x+1)\frac{2x^2+x-3}{x^2-2x-3} \div \frac{2x^2+5x+3}{x^2-4x+3} \times \frac{x^3+1}{x^3-1} = \frac{(2x+3)(x-1)}{(x-3)(x+1)} \times \frac{(x-3)(x-1)}{(2x+3)(x+1)} \times \frac{(x+1)(x^2-x+1)}{(x-1)(x^2+x+1)}

=(x−1)(x2−x+1)(x+1)(x2+x+1)= \frac{(x-1)(x^2-x+1)}{(x+1)(x^2+x+1)}

(6)

1−x21+y÷x+x21−y2×1x−1=(1−x)(1+x)1+y×(1−y)(1+y)x(1+x)×1x−1=(1−x)(1−y)x(x−1)=y−1x\frac{1-x^2}{1+y} \div \frac{x+x^2}{1-y^2} \times \frac{1}{x-1} = \frac{(1-x)(1+x)}{1+y} \times \frac{(1-y)(1+y)}{x(1+x)} \times \frac{1}{x-1} = \frac{(1-x)(1-y)}{x(x-1)} = \frac{y-1}{x}

解説: r31bn1z