第1章 1.30

(1)

2xy+ab+2ay+bx=x(b+2y)+a(b+2y)=(b+2y)(x+a)2xy + ab + 2ay + bx = x(b + 2y) + a(b + 2y) = (b + 2y)(x + a)

(2)

abbc+cab2=a(b+c)b(b+c)=(b+c)(ab)ab - bc + ca - b^2 = a(b + c) - b(b + c) = (b + c)(a - b)

(3)

x2y+x2y1=x2(y+1)(y+1)=(y+1)(x21)=(y+1)(x1)(x+1)x^2y + x^2 - y - 1 = x^2(y + 1) - (y + 1) = (y + 1)(x^2 - 1) = (y + 1)(x - 1)(x + 1)

(4)

x2y+x22xy4=xy(x2)+(x2)(x+2)=(x2)(xy+x+2)x^2y + x^2 - 2xy - 4 = xy(x - 2) + (x - 2)(x + 2) = (x - 2)(xy + x + 2)

(5)

x3+2x2y9x18y=x2(x+2y)9(x+2y)=(x+2y)(x29)=(x+2y)(x3)(x+3)x^3 + 2x^2y - 9x - 18y = x^2(x + 2y) - 9(x + 2y) = (x + 2y)(x^2 - 9) = (x + 2y)(x - 3)(x + 3)

(6)

x2+2xy+y22x2y3=(x+y)22(x+y)3={(x+y)3}{(x+y)+1}x^2 + 2xy + y^2 - 2x - 2y - 3 = (x + y)^2 - 2(x + y) - 3 = \{(x + y) - 3\}\{(x + y) + 1\}

(7)

a22b2+ab+2a+7b3=(a+2b)(ab)+2a+7b3={(a+2b)1}{(ab)+3}a^2 - 2b^2 + ab + 2a + 7b - 3 = (a + 2b)(a - b) + 2a + 7b - 3 = \{(a + 2b) - 1\}\{(a - b) + 3\}

(8)

2x2+3xy2y2+x+7y3=(2xy)(x+2y)+x+7y3={(x+2y)1}{(2xy)+3}2x^2 + 3xy - 2y^2 + x + 7y - 3 = (2x - y)(x + 2y) + x + 7y - 3 = \{(x + 2y) - 1\}\{(2x - y) + 3\}

解説: r31bn1z