第1章 1.30

(1)

2xy+ab+2ay+bx=x(b+2y)+a(b+2y)=(b+2y)(x+a)2xy + ab + 2ay + bx = x(b + 2y) + a(b + 2y) = (b + 2y)(x + a)

(2)

ab−bc+ca−b2=a(b+c)−b(b+c)=(b+c)(a−b)ab - bc + ca - b^2 = a(b + c) - b(b + c) = (b + c)(a - b)

(3)

x2y+x2−y−1=x2(y+1)−(y+1)=(y+1)(x2−1)=(y+1)(x−1)(x+1)x^2y + x^2 - y - 1 = x^2(y + 1) - (y + 1) = (y + 1)(x^2 - 1) = (y + 1)(x - 1)(x + 1)

(4)

x2y+x2−2xy−4=xy(x−2)+(x−2)(x+2)=(x−2)(xy+x+2)x^2y + x^2 - 2xy - 4 = xy(x - 2) + (x - 2)(x + 2) = (x - 2)(xy + x + 2)

(5)

x3+2x2y−9x−18y=x2(x+2y)−9(x+2y)=(x+2y)(x2−9)=(x+2y)(x−3)(x+3)x^3 + 2x^2y - 9x - 18y = x^2(x + 2y) - 9(x + 2y) = (x + 2y)(x^2 - 9) = (x + 2y)(x - 3)(x + 3)

(6)

x2+2xy+y2−2x−2y−3=(x+y)2−2(x+y)−3={(x+y)−3}{(x+y)+1}x^2 + 2xy + y^2 - 2x - 2y - 3 = (x + y)^2 - 2(x + y) - 3 = \{(x + y) - 3\}\{(x + y) + 1\}

(7)

a2−2b2+ab+2a+7b−3=(a+2b)(a−b)+2a+7b−3={(a+2b)−1}{(a−b)+3}a^2 - 2b^2 + ab + 2a + 7b - 3 = (a + 2b)(a - b) + 2a + 7b - 3 = \{(a + 2b) - 1\}\{(a - b) + 3\}

(8)

2x2+3xy−2y2+x+7y−3=(2x−y)(x+2y)+x+7y−3={(x+2y)−1}{(2x−y)+3}2x^2 + 3xy - 2y^2 + x + 7y - 3 = (2x - y)(x + 2y) + x + 7y - 3 = \{(x + 2y) - 1\}\{(2x - y) + 3\}

解説: r31bn1z