第1章 1.23

(1)

3a2ba3b×ab26a2b=b2a2\frac{3a^2b}{a^3b} \times \frac{ab^2}{6a^2b} = \frac{b}{2a^2}

(2)

5a2b6xy2÷3ab24x2y=5a2b6xy2×4x2y3ab2=10ax9by\frac{5a^2b}{6xy^2} \div \frac{3ab^2}{4x^2y} = \frac{5a^2b}{6xy^2} \times \frac{4x^2y}{3ab^2} = \frac{10ax}{9by}

(3)

2x2+4xx2−1×x−1x+2=2x(x+2)(x−1)(x+1)×x−1x+2=2xx+1\frac{2x^2+4x}{x^2-1} \times \frac{x-1}{x+2} = \frac{2x(x+2)}{(x-1)(x+1)} \times \frac{x-1}{x+2} = \frac{2x}{x+1}

(4)

a2−b2(a−b)2÷a+ba−b=(a−b)(a+b)(a−b)2×a−ba+b=1\frac{a^2-b^2}{(a-b)^2} \div \frac{a+b}{a-b} = \frac{(a-b)(a+b)}{(a-b)^2} \times \frac{a-b}{a+b} = 1

(5)

t−3t+1×(t2+5t+4)t2−9=t−3t+1×(t+1)(t+4)(t−3)(t+3)=t+4t+3\frac{t-3}{t+1} \times \frac{(t^2+5t+4)}{t^2-9} = \frac{t-3}{t+1} \times \frac{(t+1)(t+4)}{(t-3)(t+3)} = \frac{t+4}{t+3}

(6)

4a2−16a−8−a2÷2a2+5a+2a2−8−2a=(2a−1)(2a+1)−(a−4)(a−2)×(a−4)(a+2)(2a+1)(a+2)=−2a−1a−2\frac{4a^2-1}{6a-8-a^2} \div \frac{2a^2+5a+2}{a^2-8-2a} = \frac{(2a-1)(2a+1)}{-(a-4)(a-2)} \times \frac{(a-4)(a+2)}{(2a+1)(a+2)} = -\frac{2a-1}{a-2}

(7)

a2−4b23a2+2ab×3a2−ab−2b2a2−3ab+2b2=(a−2b)(a+2b)a(3a+2b)×(3a+2b)(a−b)(a−2b)(a−b)=a+2ba\frac{a^2-4b^2}{3a^2+2ab} \times \frac{3a^2-ab-2b^2}{a^2-3ab+2b^2} = \frac{(a-2b)(a+2b)}{a(3a+2b)} \times \frac{(3a+2b)(a-b)}{(a-2b)(a-b)} = \frac{a+2b}{a}

解説: r31bn1z